Integrand size = 28, antiderivative size = 125 \[ \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}} \, dx=-\frac {10 \sqrt {1-2 x} \sqrt {2+3 x}}{33 (3+5 x)^{3/2}}+\frac {620 \sqrt {1-2 x} \sqrt {2+3 x}}{363 \sqrt {3+5 x}}-\frac {124 E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{11 \sqrt {33}}-\frac {4 \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )}{11 \sqrt {33}} \]
-124/363*EllipticE(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)-4/ 363*EllipticF(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)-10/33*( 1-2*x)^(1/2)*(2+3*x)^(1/2)/(3+5*x)^(3/2)+620/363*(1-2*x)^(1/2)*(2+3*x)^(1/ 2)/(3+5*x)^(1/2)
Result contains complex when optimal does not.
Time = 2.62 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.74 \[ \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}} \, dx=\frac {2}{363} \left (\frac {25 \sqrt {1-2 x} \sqrt {2+3 x} (35+62 x)}{(3+5 x)^{3/2}}+62 i \sqrt {33} E\left (i \text {arcsinh}\left (\sqrt {9+15 x}\right )|-\frac {2}{33}\right )-64 i \sqrt {33} \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {9+15 x}\right ),-\frac {2}{33}\right )\right ) \]
(2*((25*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*(35 + 62*x))/(3 + 5*x)^(3/2) + (62*I)* Sqrt[33]*EllipticE[I*ArcSinh[Sqrt[9 + 15*x]], -2/33] - (64*I)*Sqrt[33]*Ell ipticF[I*ArcSinh[Sqrt[9 + 15*x]], -2/33]))/363
Time = 0.22 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.08, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {115, 169, 27, 176, 123, 129}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{5/2}} \, dx\) |
\(\Big \downarrow \) 115 |
\(\displaystyle -\frac {2}{33} \int \frac {22-15 x}{\sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{3/2}}dx-\frac {10 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 169 |
\(\displaystyle -\frac {2}{33} \left (-\frac {2}{11} \int \frac {3 (310 x+197)}{2 \sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-\frac {310 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {10 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {2}{33} \left (-\frac {3}{11} \int \frac {310 x+197}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-\frac {310 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {10 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 176 |
\(\displaystyle -\frac {2}{33} \left (-\frac {3}{11} \left (11 \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx+62 \int \frac {\sqrt {5 x+3}}{\sqrt {1-2 x} \sqrt {3 x+2}}dx\right )-\frac {310 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {10 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 123 |
\(\displaystyle -\frac {2}{33} \left (-\frac {3}{11} \left (11 \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-62 \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )\right )-\frac {310 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {10 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 129 |
\(\displaystyle -\frac {2}{33} \left (-\frac {3}{11} \left (-2 \sqrt {\frac {11}{3}} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )-62 \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )\right )-\frac {310 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {10 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\) |
(-10*Sqrt[1 - 2*x]*Sqrt[2 + 3*x])/(33*(3 + 5*x)^(3/2)) - (2*((-310*Sqrt[1 - 2*x]*Sqrt[2 + 3*x])/(11*Sqrt[3 + 5*x]) - (3*(-62*Sqrt[11/3]*EllipticE[Ar cSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33] - 2*Sqrt[11/3]*EllipticF[ArcSin[Sqrt [3/7]*Sqrt[1 - 2*x]], 35/33]))/11))/33
3.29.80.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[b*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1 )/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + Simp[1/((m + 1)*(b*c - a*d)*(b*e - a*f)) Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*(m + 1) - b*(d*e*(m + n + 2) + c*f*(m + p + 2)) - b*d*f*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && LtQ[m, -1] && IntegersQ[2*m, 2 *n, 2*p]
Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_ )]), x_] :> Simp[(2/b)*Rt[-(b*e - a*f)/d, 2]*EllipticE[ArcSin[Sqrt[a + b*x] /Rt[-(b*c - a*d)/d, 2]], f*((b*c - a*d)/(d*(b*e - a*f)))], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] && !L tQ[-(b*c - a*d)/d, 0] && !(SimplerQ[c + d*x, a + b*x] && GtQ[-d/(b*c - a*d ), 0] && GtQ[d/(d*e - c*f), 0] && !LtQ[(b*c - a*d)/b, 0])
Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x _)]), x_] :> Simp[2*(Rt[-b/d, 2]/(b*Sqrt[(b*e - a*f)/b]))*EllipticF[ArcSin[ Sqrt[a + b*x]/(Rt[-b/d, 2]*Sqrt[(b*c - a*d)/b])], f*((b*c - a*d)/(d*(b*e - a*f)))], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ [(b*e - a*f)/b, 0] && PosQ[-b/d] && !(SimplerQ[c + d*x, a + b*x] && GtQ[(d *e - c*f)/d, 0] && GtQ[-d/b, 0]) && !(SimplerQ[c + d*x, a + b*x] && GtQ[(( -b)*e + a*f)/f, 0] && GtQ[-f/b, 0]) && !(SimplerQ[e + f*x, a + b*x] && GtQ [((-d)*e + c*f)/f, 0] && GtQ[((-b)*e + a*f)/f, 0] && (PosQ[-f/d] || PosQ[-f /b]))
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + S imp[1/((m + 1)*(b*c - a*d)*(b*e - a*f)) Int[(a + b*x)^(m + 1)*(c + d*x)^n *(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a* h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegersQ[ 2*m, 2*n, 2*p]
Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]* Sqrt[(e_) + (f_.)*(x_)]), x_] :> Simp[h/f Int[Sqrt[e + f*x]/(Sqrt[a + b*x ]*Sqrt[c + d*x]), x], x] + Simp[(f*g - e*h)/f Int[1/(Sqrt[a + b*x]*Sqrt[c + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && Sim plerQ[a + b*x, e + f*x] && SimplerQ[c + d*x, e + f*x]
Leaf count of result is larger than twice the leaf count of optimal. \(218\) vs. \(2(93)=186\).
Time = 1.40 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.75
method | result | size |
default | \(-\frac {2 \left (10560 \sqrt {5}\, \sqrt {7}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}-10850 \sqrt {5}\, \sqrt {7}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}+6336 \sqrt {5}\, \sqrt {2+3 x}\, \sqrt {7}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )-6510 \sqrt {5}\, \sqrt {2+3 x}\, \sqrt {7}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )-325500 x^{3}-238000 x^{2}+77875 x +61250\right ) \sqrt {2+3 x}\, \sqrt {1-2 x}}{12705 \left (6 x^{2}+x -2\right ) \left (3+5 x \right )^{\frac {3}{2}}}\) | \(219\) |
elliptic | \(\frac {\sqrt {-\left (-1+2 x \right ) \left (3+5 x \right ) \left (2+3 x \right )}\, \left (\frac {788 \sqrt {10+15 x}\, \sqrt {21-42 x}\, \sqrt {-15 x -9}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{12705 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}+\frac {248 \sqrt {10+15 x}\, \sqrt {21-42 x}\, \sqrt {-15 x -9}\, \left (-\frac {7 E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{6}+\frac {F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{2}\right )}{2541 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}-\frac {2 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}{165 \left (x +\frac {3}{5}\right )^{2}}+\frac {-\frac {1240}{121} x^{2}-\frac {620}{363} x +\frac {1240}{363}}{\sqrt {\left (x +\frac {3}{5}\right ) \left (-30 x^{2}-5 x +10\right )}}\right )}{\sqrt {1-2 x}\, \sqrt {2+3 x}\, \sqrt {3+5 x}}\) | \(219\) |
-2/12705*(10560*5^(1/2)*7^(1/2)*EllipticF((10+15*x)^(1/2),1/35*70^(1/2))*x *(2+3*x)^(1/2)*(1-2*x)^(1/2)*(-3-5*x)^(1/2)-10850*5^(1/2)*7^(1/2)*Elliptic E((10+15*x)^(1/2),1/35*70^(1/2))*x*(2+3*x)^(1/2)*(1-2*x)^(1/2)*(-3-5*x)^(1 /2)+6336*5^(1/2)*(2+3*x)^(1/2)*7^(1/2)*(1-2*x)^(1/2)*(-3-5*x)^(1/2)*Ellipt icF((10+15*x)^(1/2),1/35*70^(1/2))-6510*5^(1/2)*(2+3*x)^(1/2)*7^(1/2)*(1-2 *x)^(1/2)*(-3-5*x)^(1/2)*EllipticE((10+15*x)^(1/2),1/35*70^(1/2))-325500*x ^3-238000*x^2+77875*x+61250)*(2+3*x)^(1/2)*(1-2*x)^(1/2)/(6*x^2+x-2)/(3+5* x)^(3/2)
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.07 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.70 \[ \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}} \, dx=\frac {2 \, {\left (225 \, {\left (62 \, x + 35\right )} \sqrt {5 \, x + 3} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1} - 212 \, \sqrt {-30} {\left (25 \, x^{2} + 30 \, x + 9\right )} {\rm weierstrassPInverse}\left (\frac {1159}{675}, \frac {38998}{91125}, x + \frac {23}{90}\right ) + 558 \, \sqrt {-30} {\left (25 \, x^{2} + 30 \, x + 9\right )} {\rm weierstrassZeta}\left (\frac {1159}{675}, \frac {38998}{91125}, {\rm weierstrassPInverse}\left (\frac {1159}{675}, \frac {38998}{91125}, x + \frac {23}{90}\right )\right )\right )}}{3267 \, {\left (25 \, x^{2} + 30 \, x + 9\right )}} \]
2/3267*(225*(62*x + 35)*sqrt(5*x + 3)*sqrt(3*x + 2)*sqrt(-2*x + 1) - 212*s qrt(-30)*(25*x^2 + 30*x + 9)*weierstrassPInverse(1159/675, 38998/91125, x + 23/90) + 558*sqrt(-30)*(25*x^2 + 30*x + 9)*weierstrassZeta(1159/675, 389 98/91125, weierstrassPInverse(1159/675, 38998/91125, x + 23/90)))/(25*x^2 + 30*x + 9)
\[ \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}} \, dx=\int \frac {1}{\sqrt {1 - 2 x} \sqrt {3 x + 2} \left (5 x + 3\right )^{\frac {5}{2}}}\, dx \]
\[ \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}} \, dx=\int { \frac {1}{{\left (5 \, x + 3\right )}^{\frac {5}{2}} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1}} \,d x } \]
\[ \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}} \, dx=\int { \frac {1}{{\left (5 \, x + 3\right )}^{\frac {5}{2}} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1}} \,d x } \]
Timed out. \[ \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}} \, dx=\int \frac {1}{\sqrt {1-2\,x}\,\sqrt {3\,x+2}\,{\left (5\,x+3\right )}^{5/2}} \,d x \]